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#1147
bernadette
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Un truc comme cela

 

integer{a=randint(-10..-1)*randint(1..10)}
integer{b=randint(1..10)}
integer{c=randint(-10..10)}
function{tg=frac{1}{k},frac{1}{k^2},frac{k}{k+1},k,k^2,k^3,a*k+b,a*k,sqrt(k),(a*k+b)^2}

integer{i=randint(1..10)}
text{reponses=demander n, u prend la valeur 0, tant que k (leq) n,
 u prend la valeur u+evalue(tg,k),k prend la valeur k+1,
fin tant que,afficher u}
statement{
<p>
On considère la suite ((u_{n})) définie, pour tout entier n>0, par
(displaystyle{u_{n}=sum_{k=1}^{n}tgtext}). Ecrire un algorithme permettant de calculer
le terme (u_n)
</p>
embed{r1,100×20 x 1}
<br/>
embed{r2,100×20 x 1}
<br/>
embed{r3,100×20 x 1}
<br/>
embed{r4,100×20 x 1}
<br/>
embed{r5,100×20 x 1}
<br/>
embed{r6,100×20 x 1}
<br/>
embed{r7,100×20 x 1}
}
answer{}{reponseleve1;reponses}{type=clickfill}{option=shuffle}
answer{}{reponseleve2;reponses}{type=clickfill}{option=shuffle}
answer{}{reponseleve3;reponses}{type=clickfill}{option=shuffle}
answer{}{reponseleve4;reponses}{type=clickfill}{option=shuffle}
answer{}{reponseleve5;reponses}{type=clickfill}{option=shuffle}
answer{}{reponseleve6;reponses}{type=clickfill}{option=shuffle}
answer{}{reponseleve7;reponses}{type=clickfill}{option=shuffle}

text{reponseleve=reponseleve1,reponseleve2,reponseleve3,reponseleve4,reponseleve5,reponseleve6,reponseleve7}
text{test=((reponseleve[4] issametex reponses[4] and reponseleve[5] issametex reponses[5])
or (reponseleve[4] issametex reponses[5] and reponseleve[5] issametex reponses[4]) )
and (reponseleve[1] issametex reponses[1] and reponseleve[2] issametex reponses[2] and reponseleve[3] issametex reponses[3] and reponseleve[6] issametex reponses[6] and reponseleve[7] issametex reponses[7])?1:0}
condition{}{test=1}

Bien sûr il faut aussi mettre des feedback.

Bernadette