Rev 4562 | Rev 5921 | Go to most recent revision | Details | Compare with Previous | Last modification | View Log | RSS feed
| Rev | Author | Line No. | Line |
|---|---|---|---|
| 32 | reyssat | 1 | !! +var+ +exec+ +string+ |
| 2 | $lst_tit solve$lst_titend$type_both |
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| 4562 | bpr | 3 | $lst_alias rootof |
| 32 | reyssat | 4 | $(lst_syntax)solve $emph fn$emphend for $emph v$emphend=$emph v1$emphend |
| 4562 | bpr | 5 | to $emph v2$emphend</tt> |
| 32 | reyssat | 6 | $lst_mean Find out (real simple) roots of the function/equation |
| 7 | $emph fn$emphend |
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| 8 | for the variable $emph v$emphend between $emph v1$emphend and |
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| 9 | $emph v2$emphend. <p> |
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| 10 | $emph fn$emphend may have several roots in the interval [v1,v2], but |
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| 11 | roots too close to each other may be overlooked. |
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| 5920 | bpr | 12 | </p> |