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$lst_tit makelist$lst_titend$type_both

tit:makelist

  $(lst_syntax)makelist $emph templ$emphend for $emph v$emphend=$emph v1$emphend

type:$type_both

  to $emph v2$emphend [step $emph st $emphend], or <br/>

syntax:!makelist `templ' for `v'=`v1' to `v2' [step `st'], or <br/>

$ !makelist $emph templ$emphend for $emph v$emphend in

$ !makelist `templ' for `v' in `v1,v2,v3,...'

  $lst_mean Outputs a list consisting of $emph templ$emphend with

mean:Outputs a list consisting of `templ' with variable `v' successively substituted \

  ..., $emph v2$emphend. <p>

  by values `v1', ..., `v2'. <p>\

  In the second syntax, the substitutions are done with respect to each item in

  In the second syntax, the substitutions are done with respect to each item in\

  the list $emph v1,v2,...$emphend. </p><p>

  the list `v1,v2,...'. </p><p>\

  The variable $emph v $emphend should appear in $emph templ $emphend

  The variable `v' should appear in `templ' as a math variable \

  as a math variable (that is, with no preceeding character). </p><p>

  (that is, with no preceeding character). </p><p>For example, the command</p>\

<pre>!makelist [x;x+1;xx] for x in a,x and y,1,(2,3)</pre>

<pre>!makelist [x;x+1;xx] for x in a,x and y,1,(2,3)</pre>\

  gives the result

  gives the result\

  <pre>

  <pre>\

  !makelist [x;x+1;xx] for x in a,x and y,1,(2,3)

  !makelist [x;x+1;xx] for x in a,x and y,1,(2,3)\